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9m^2-8m-20=0
a = 9; b = -8; c = -20;
Δ = b2-4ac
Δ = -82-4·9·(-20)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-28}{2*9}=\frac{-20}{18} =-1+1/9 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+28}{2*9}=\frac{36}{18} =2 $
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